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# thekeele's solution

## to Sublist in the Elixir Track

Published at May 09 2019 · 0 comments
Instructions
Test suite
Solution

#### Note:

This exercise has changed since this solution was written.

Given two lists determine if the first list is contained within the second list, if the second list is contained within the first list, if both lists are contained within each other or if none of these are true.

Specifically, a list A is a sublist of list B if by dropping 0 or more elements from the front of B and 0 or more elements from the back of B you get a list that's completely equal to A.

Examples:

• A = [1, 2, 3], B = [1, 2, 3, 4, 5], A is a sublist of B
• A = [3, 4, 5], B = [1, 2, 3, 4, 5], A is a sublist of B
• A = [3, 4], B = [1, 2, 3, 4, 5], A is a sublist of B
• A = [1, 2, 3], B = [1, 2, 3], A is equal to B
• A = [1, 2, 3, 4, 5], B = [2, 3, 4], A is a superlist of B
• A = [1, 2, 4], B = [1, 2, 3, 4, 5], A is not a superlist of, sublist of or equal to B

## Running tests

Execute the tests with:

\$ elixir sublist_test.exs

### Pending tests

In the test suites, all but the first test have been skipped.

Once you get a test passing, you can unskip the next one by commenting out the relevant @tag :pending with a # symbol.

For example:

# @tag :pending
test "shouting" do
assert Bob.hey("WATCH OUT!") == "Whoa, chill out!"
end

Or, you can enable all the tests by commenting out the ExUnit.configure line in the test suite.

# ExUnit.configure exclude: :pending, trace: true

If you're stuck on something, it may help to look at some of the available resources out there where answers might be found.

## Submitting Incomplete Solutions

It's possible to submit an incomplete solution so you can see how others have completed the exercise.

### sublist_test.exs

if !System.get_env("EXERCISM_TEST_EXAMPLES") do
end

ExUnit.start()
ExUnit.configure(exclude: :pending, trace: true)

defmodule SublistTest do
use ExUnit.Case

test "empty equals empty" do
assert Sublist.compare([], []) == :equal
end

@tag :pending
test "empty is a sublist of anything" do
assert Sublist.compare([], [nil]) == :sublist
end

@tag :pending
test "anything is a superlist of empty" do
assert Sublist.compare([nil], []) == :superlist
end

@tag :pending
test "1 is not 2" do
assert Sublist.compare([1], [2]) == :unequal
end

@tag :pending
test "comparing massive equal lists" do
l = Enum.to_list(1..1_000_000)
assert Sublist.compare(l, l) == :equal
end

@tag :pending
test "sublist at start" do
assert Sublist.compare([1, 2, 3], [1, 2, 3, 4, 5]) == :sublist
end

@tag :pending
test "sublist in middle" do
assert Sublist.compare([4, 3, 2], [5, 4, 3, 2, 1]) == :sublist
end

@tag :pending
test "sublist at end" do
assert Sublist.compare([3, 4, 5], [1, 2, 3, 4, 5]) == :sublist
end

@tag :pending
test "partially matching sublist at start" do
assert Sublist.compare([1, 1, 2], [1, 1, 1, 2]) == :sublist
end

@tag :pending
test "sublist early in huge list" do
assert Sublist.compare([3, 4, 5], Enum.to_list(1..1_000_000)) == :sublist
end

@tag :pending
test "huge sublist not in huge list" do
assert Sublist.compare(Enum.to_list(10..1_000_001), Enum.to_list(1..1_000_000)) == :unequal
end

@tag :pending
test "superlist at start" do
assert Sublist.compare([1, 2, 3, 4, 5], [1, 2, 3]) == :superlist
end

@tag :pending
test "superlist in middle" do
assert Sublist.compare([5, 4, 3, 2, 1], [4, 3, 2]) == :superlist
end

@tag :pending
test "superlist at end" do
assert Sublist.compare([1, 2, 3, 4, 5], [3, 4, 5]) == :superlist
end

@tag :pending
test "1 and 2 does not contain 3" do
assert Sublist.compare([1, 2], [3]) == :unequal
end

@tag :pending
test "partially matching superlist at start" do
assert Sublist.compare([1, 1, 1, 2], [1, 1, 2]) == :superlist
end

@tag :pending
test "superlist early in huge list" do
assert Sublist.compare(Enum.to_list(1..1_000_000), [3, 4, 5]) == :superlist
end

@tag :pending
test "strict equality needed" do
assert Sublist.compare([1], [1.0, 2]) == :unequal
end

@tag :pending
test "recurring values sublist" do
assert Sublist.compare([1, 2, 1, 2, 3], [1, 2, 3, 1, 2, 1, 2, 3, 2, 1]) == :sublist
end

@tag :pending
test "recurring values unequal" do
assert Sublist.compare([1, 2, 1, 2, 3], [1, 2, 3, 1, 2, 3, 2, 3, 2, 1]) == :unequal
end
end
defmodule Sublist do

def compare(a, b) do
cond do
a === b -> :equal
sublist?(a, b) -> :sublist
sublist?(b, a) -> :superlist
true -> :unequal
end
end

def sublist?(_, []), do: false
def sublist?(a, b) do
List.starts_with?(b, a) or sublist?(a, tl(b))
end
end