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jorgemario's solution

to Anagram in the Clojure Track

Published at Jul 13 2018 · 1 comment
Instructions
Test suite
Solution

Given a word and a list of possible anagrams, select the correct sublist.

Given "listen" and a list of candidates like "enlists" "google" "inlets" "banana" the program should return a list containing "inlets".

Source

Inspired by the Extreme Startup game https://github.com/rchatley/extreme_startup

Submitting Incomplete Solutions

It's possible to submit an incomplete solution so you can see how others have completed the exercise.

anagram_test.clj

(ns anagram-test
  (:require [clojure.test :refer [deftest is]]
            anagram))

(deftest no-matches
  (is (= []
         (anagram/anagrams-for "diaper" ["hello" "world" "zombies" "pants"]))))

(deftest detect-simple-anagram
  (is (= ["tan"] (anagram/anagrams-for "ant" ["tan" "stand" "at"]))))

(deftest does-not-confuse-different-duplicates
  (is (= [] (anagram/anagrams-for "galea" ["eagle"]))))

(deftest eliminate-anagram-subsets
  (is (= [] (anagram/anagrams-for "good" ["dog" "goody"]))))

(deftest detect-anagram
  (is (= ["inlets"]
         (let [coll ["enlists" "google" "inlets" "banana"]]
           (anagram/anagrams-for "listen" coll)))))

(deftest multiple-anagrams
  (is (= ["gallery" "regally" "largely"]
         (let [coll ["gallery" "ballerina" "regally"
                     "clergy"  "largely"   "leading"]]
           (anagram/anagrams-for "allergy" coll)))))

(deftest case-insensitive-anagrams
  (is (= ["Carthorse"]
         (let [coll ["cashregister" "Carthorse" "radishes"]]
           (anagram/anagrams-for "Orchestra" coll)))))

(deftest word-is-not-own-anagram
  (is (= [] (anagram/anagrams-for "banana" ["banana"]))))

(deftest capital-word-is-not-own-anagram
  (is (= [] (anagram/anagrams-for "BANANA" ["banana"]))))
(ns anagram
  (:require [clojure.string :refer [lower-case]]))

(defn freq-map [word]
  (frequencies (lower-case word)))

(defn is-anagram? [word candidate]
  "Returns a function that allows to compare an specific word against
  anagram candidates. It does resolve the predicate by creating frequency
  maps of each character and comparing the resulting maps. 
  Also, a particular word is not an anagram of itself."
  (and (not (.equalsIgnoreCase word candidate))
       (= (freq-map word) (freq-map candidate))))

(defn anagrams-for [word candidates] ;; <- arglist goes here
  (let [filter-fn (partial is-anagram? word)]
    (filter filter-fn candidates)))

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Avatar of jorgemario

Iteration 2: using newly discovered functions: frequencies and partial.

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