Determine if a number is perfect, abundant, or deficient based on Nicomachus' (60 - 120 CE) classification scheme for natural numbers.
The Greek mathematician Nicomachus devised a classification scheme for natural numbers, identifying each as belonging uniquely to the categories of perfect, abundant, or deficient based on their aliquot sum. The aliquot sum is defined as the sum of the factors of a number not including the number itself. For example, the aliquot sum of 15 is (1 + 3 + 5) = 9
Implement a way to determine whether a given number is perfect. Depending on your language track, you may also need to implement a way to determine whether a given number is abundant or deficient.
The Scala exercises assume an SBT project scheme. The exercise solution source should be placed within the exercise directory/src/main/scala. The exercise unit tests can be found within the exercise directory/src/test/scala.
To run the tests simply run the command sbt test
in the exercise directory.
Please see the learning and installation pages if you need any help.
Taken from Chapter 2 of Functional Thinking by Neal Ford. http://shop.oreilly.com/product/0636920029687.do
It's possible to submit an incomplete solution so you can see how others have completed the exercise.
import org.scalatest.{Matchers, FunSuite}
/** @version 1.1.0 */
class PerfectNumbersTest extends FunSuite with Matchers {
test("Smallest perfect number is classified correctly") {
PerfectNumbers.classify(6) should be(Right(NumberType.Perfect))
}
test("Medium perfect number is classified correctly") {
pending
PerfectNumbers.classify(28) should be(Right(NumberType.Perfect))
}
test("Large perfect number is classified correctly") {
pending
PerfectNumbers.classify(33550336) should be(Right(NumberType.Perfect))
}
test("Smallest abundant number is classified correctly") {
pending
PerfectNumbers.classify(12) should be(Right(NumberType.Abundant))
}
test("Medium abundant number is classified correctly") {
pending
PerfectNumbers.classify(30) should be(Right(NumberType.Abundant))
}
test("Large abundant number is classified correctly") {
pending
PerfectNumbers.classify(33550335) should be(Right(NumberType.Abundant))
}
test("Smallest prime deficient number is classified correctly") {
pending
PerfectNumbers.classify(2) should be(Right(NumberType.Deficient))
}
test("Smallest non-prime deficient number is classified correctly") {
pending
PerfectNumbers.classify(4) should be(Right(NumberType.Deficient))
}
test("Medium deficient number is classified correctly") {
pending
PerfectNumbers.classify(32) should be(Right(NumberType.Deficient))
}
test("Large deficient number is classified correctly") {
pending
PerfectNumbers.classify(33550337) should be(Right(NumberType.Deficient))
}
test("Edge case (no factors other than itself) is classified correctly") {
pending
PerfectNumbers.classify(1) should be(Right(NumberType.Deficient))
}
test("Zero is rejected (not a natural number)") {
pending
PerfectNumbers.classify(0) should be(
Left("Classification is only possible for natural numbers."))
}
test("Negative integer is rejected (not a natural number)") {
pending
PerfectNumbers.classify(-1) should be(
Left("Classification is only possible for natural numbers."))
}
}
import NumberType.NumberType
object PerfectNumbers {
def classify(n: Int) = {
if (n <= 0) Left("Classification is only possible for natural numbers.")
else {
val v = aliquot(n).sum
v match {
case num if num == n => Right(NumberType.Perfect)
case num if num > n => Right(NumberType.Abundant)
case num if num < n => Right(NumberType.Deficient)
}
}
}
private def aliquot(num: Int): Vector[Int] = {
(1 to num / 2).toVector.filter(num % _ == 0)
}
}
object NumberType extends Enumeration {
type NumberType = Value
val Perfect, Abundant, Deficient = Value
}
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