Given a string of digits, calculate the largest product for a contiguous substring of digits of length n.
For example, for the input '1027839564'
, the largest product for a
series of 3 digits is 270 (9 * 5 * 6), and the largest product for a
series of 5 digits is 7560 (7 * 8 * 3 * 9 * 5).
Note that these series are only required to occupy adjacent positions in the input; the digits need not be numerically consecutive.
For the input '73167176531330624919225119674426574742355349194934'
,
the largest product for a series of 6 digits is 23520.
For installation and learning resources, refer to the exercism help page.
For running the tests provided, you will need the Minitest gem. Open a terminal window and run the following command to install minitest:
gem install minitest
If you would like color output, you can require 'minitest/pride'
in
the test file, or note the alternative instruction, below, for running
the test file.
Run the tests from the exercise directory using the following command:
ruby largest_series_product_test.rb
To include color from the command line:
ruby -r minitest/pride largest_series_product_test.rb
A variation on Problem 8 at Project Euler http://projecteuler.net/problem=8
It's possible to submit an incomplete solution so you can see how others have completed the exercise.
require 'minitest/autorun'
require_relative 'largest_series_product'
# Common test data version: 1.0.0 e79b832
class LargestSeriesProductTest < Minitest::Test
def test_finds_the_largest_product_if_span_equals_length
# skip
assert_equal 18, Series.new('29').largest_product(2)
end
def test_can_find_the_largest_product_of_2_with_numbers_in_order
skip
assert_equal 72, Series.new('0123456789').largest_product(2)
end
def test_can_find_the_largest_product_of_2
skip
assert_equal 48, Series.new('576802143').largest_product(2)
end
def test_can_find_the_largest_product_of_3_with_numbers_in_order
skip
assert_equal 504, Series.new('0123456789').largest_product(3)
end
def test_can_find_the_largest_product_of_3
skip
assert_equal 270, Series.new('1027839564').largest_product(3)
end
def test_can_find_the_largest_product_of_5_with_numbers_in_order
skip
assert_equal 15120, Series.new('0123456789').largest_product(5)
end
def test_can_get_the_largest_product_of_a_big_number
skip
assert_equal 23520, Series.new('73167176531330624919225119674426574742355349194934').largest_product(6)
end
def test_reports_zero_if_the_only_digits_are_zero
skip
assert_equal 0, Series.new('0000').largest_product(2)
end
def test_reports_zero_if_all_spans_include_zero
skip
assert_equal 0, Series.new('99099').largest_product(3)
end
def test_rejects_span_longer_than_string_length
skip
assert_raises(ArgumentError) { Series.new('123').largest_product(4) }
end
def test_reports_1_for_empty_string_and_empty_product_0_span
skip
assert_equal 1, Series.new('').largest_product(0)
end
def test_reports_1_for_nonempty_string_and_empty_product_0_span
skip
assert_equal 1, Series.new('123').largest_product(0)
end
def test_rejects_empty_string_and_nonzero_span
skip
assert_raises(ArgumentError) { Series.new('').largest_product(1) }
end
def test_rejects_invalid_character_in_digits
skip
assert_raises(ArgumentError) { Series.new('1234a5').largest_product(2) }
end
def test_rejects_negative_span
skip
assert_raises(ArgumentError) { Series.new('12345').largest_product(-1) }
end
# Problems in exercism evolve over time, as we find better ways to ask
# questions.
# The version number refers to the version of the problem you solved,
# not your solution.
#
# Define a constant named VERSION inside of the top level BookKeeping
# module, which may be placed near the end of your file.
#
# In your file, it will look like this:
#
# module BookKeeping
# VERSION = 1 # Where the version number matches the one in the test.
# end
#
# If you are curious, read more about constants on RubyDoc:
# http://ruby-doc.org/docs/ruby-doc-bundle/UsersGuide/rg/constants.html
def test_bookkeeping
skip
assert_equal 3, BookKeeping::VERSION
end
end
class Series
attr_reader :digits
def initialize(digits)
raise ArgumentError if digits =~ /[^0-9]/
@digits = digits.chars.map(&:to_i)
end
def largest_product(num)
raise ArgumentError if num > digits.length || num < 0
(0..(digits.length - num)).lazy.map do |i|
digits[i...(i + num)]
end.map do |sequence|
sequence.inject(1, :*)
end.max
end
end
module BookKeeping
VERSION = 2
end
A huge amount can be learned from reading other people’s code. This is why we wanted to give exercism users the option of making their solutions public.
Here are some questions to help you reflect on this solution and learn the most from it.
Level up your programming skills with 3,122 exercises across 52 languages, and insightful discussion with our volunteer team of welcoming mentors. Exercism is 100% free forever.
Sign up Learn More
Community comments
Was playing with .lazy trying to figure out how to lazily generate subsequences, find the sum and then store only one max amount.