 # rootulp's solution

## to Binary Search in the Ruby Track

Published at Jul 13 2018 · 0 comments
Instructions
Test suite
Solution

#### Note:

This solution was written on an old version of Exercism. The tests below might not correspond to the solution code, and the exercise may have changed since this code was written.

Implement a binary search algorithm.

Searching a sorted collection is a common task. A dictionary is a sorted list of word definitions. Given a word, one can find its definition. A telephone book is a sorted list of people's names, addresses, and telephone numbers. Knowing someone's name allows one to quickly find their telephone number and address.

If the list to be searched contains more than a few items (a dozen, say) a binary search will require far fewer comparisons than a linear search, but it imposes the requirement that the list be sorted.

In computer science, a binary search or half-interval search algorithm finds the position of a specified input value (the search "key") within an array sorted by key value.

In each step, the algorithm compares the search key value with the key value of the middle element of the array.

If the keys match, then a matching element has been found and its index, or position, is returned.

Otherwise, if the search key is less than the middle element's key, then the algorithm repeats its action on the sub-array to the left of the middle element or, if the search key is greater, on the sub-array to the right.

If the remaining array to be searched is empty, then the key cannot be found in the array and a special "not found" indication is returned.

A binary search halves the number of items to check with each iteration, so locating an item (or determining its absence) takes logarithmic time. A binary search is a dichotomic divide and conquer search algorithm.

For installation and learning resources, refer to the exercism help page.

For running the tests provided, you will need the Minitest gem. Open a terminal window and run the following command to install minitest:

``````gem install minitest
``````

If you would like color output, you can `require 'minitest/pride'` in the test file, or note the alternative instruction, below, for running the test file.

Run the tests from the exercise directory using the following command:

``````ruby binary_search_test.rb
``````

To include color from the command line:

``````ruby -r minitest/pride binary_search_test.rb
``````

## Submitting Incomplete Solutions

It's possible to submit an incomplete solution so you can see how others have completed the exercise.

### binary_search_test.rb

``````require 'minitest/autorun'
require_relative 'binary_search'

class BinarySearchTest < Minitest::Test
def test_it_has_list_data
binary = BinarySearch.new([1, 3, 4, 6, 8, 9, 11])
assert_equal [1, 3, 4, 6, 8, 9, 11], binary.list
end

def test_it_raises_error_for_unsorted_list
skip
assert_raises ArgumentError do
BinarySearch.new([2, 1, 4, 3, 6])
end
end

def test_it_raises_error_for_data_not_in_list
skip
assert_raises RuntimeError do
BinarySearch.new([1, 3, 6]).search_for(2)
end
end

def test_it_finds_position_of_middle_item
skip
binary = BinarySearch.new([1, 3, 4, 6, 8, 9, 11])
assert_equal 3, binary.middle
end

def test_it_finds_position_of_search_data
skip
binary = BinarySearch.new([1, 3, 4, 6, 8, 9, 11])
assert_equal 5, binary.search_for(9)
end

def test_it_finds_position_in_a_larger_list
skip
binary = BinarySearch.new([1, 3, 5, 8, 13, 21, 34, 55, 89, 144])
assert_equal 1, binary.search_for(3)
assert_equal 7, binary.search_for(55)
end

def test_it_finds_correct_position_in_a_list_with_an_even_number_of_elements
skip
binary = BinarySearch.new([1, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377])
assert_equal 5, binary.search_for(21)
assert_equal 6, binary.search_for(34)
end
end``````
``````# Performs a Binary Search for a particular int in an array
class BinarySearch
def initialize(list)
@list = list
raise ArgumentError if list != list.sort
end

def search_for(val)
search(val, 0, list.size - 1)
end

def middle(left = 0, right = list.size - 1)
(left + right) / 2
end

private

def search(val, left, right)
raise RuntimeError if left >= right

mid = middle(left, right)
if val < list[mid]
search(val, left, mid - 1)
elsif val > list[mid]
search(val, mid + 1, right)
else
mid
end
end
end``````