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NunoSempere's solution

to Pangram in the OCaml Track

Published at Dec 29 2019 · 0 comments
Test suite

Determine if a sentence is a pangram. A pangram (Greek: παν γράμμα, pan gramma, "every letter") is a sentence using every letter of the alphabet at least once. The best known English pangram is:

The quick brown fox jumps over the lazy dog.

The alphabet used consists of ASCII letters a to z, inclusive, and is case insensitive. Input will not contain non-ASCII symbols.

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Wikipedia https://en.wikipedia.org/wiki/Pangram


(* pangram - 1.4.1 *)
open OUnit2
open Pangram

let ae exp got _test_ctxt = assert_equal ~printer:string_of_bool exp got

let tests = [
  "sentence empty" >::
  ae false (is_pangram "");
  "recognizes a perfect lower case pangram" >::
  ae true (is_pangram "abcdefghijklmnopqrstuvwxyz");
  "pangram with only lower case" >::
  ae true (is_pangram "the quick brown fox jumps over the lazy dog");
  "missing character 'x'" >::
  ae false (is_pangram "a quick movement of the enemy will jeopardize five gunboats");
  "another missing character, e.g. 'h'" >::
  ae false (is_pangram "five boxing wizards jump quickly at it");
  "pangram with underscores" >::
  ae true (is_pangram "the_quick_brown_fox_jumps_over_the_lazy_dog");
  "pangram with numbers" >::
  ae true (is_pangram "the 1 quick brown fox jumps over the 2 lazy dogs");
  "missing letters replaced by numbers" >::
  ae false (is_pangram "7h3 qu1ck brown fox jumps ov3r 7h3 lazy dog");
  "pangram with mixed case and punctuation" >::
  ae true (is_pangram "\"Five quacking Zephyrs jolt my wax bed.\"");
  "upper and lower case versions of the same character should not be counted separately" >::
  ae false (is_pangram "the quick brown fox jumps over with lazy FX");

let () =
  run_test_tt_main ("pangram tests" >::: tests)
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let explode s = List.init (String.length s) (String.get s)
let alphabetLetterList = explode alphabet

let is_pangram string =
    let cList = explode (String.lowercase_ascii string) in
    let isInPhrase c = List.mem c cList in (*Is c a member of cList?*)
    not (List.mem false (List.map isInPhrase alphabetLetterList))

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