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JaeHyoLee's solution

to Accumulate in the Lua Track

Published at Jul 13 2018 · 1 comment
Test suite

Implement the accumulate operation, which, given a collection and an operation to perform on each element of the collection, returns a new collection containing the result of applying that operation to each element of the input collection.

Given the collection of numbers:

  • 1, 2, 3, 4, 5

And the operation:

  • square a number (x => x * x)

Your code should be able to produce the collection of squares:

  • 1, 4, 9, 16, 25

Check out the test suite to see the expected function signature.


Keep your hands off that collect/map/fmap/whatchamacallit functionality provided by your standard library! Solve this one yourself using other basic tools instead.

Running the tests

To run the tests, run the command busted from within the exercise directory.

Further information

For more detailed information about the Lua track, including how to get help if you're having trouble, please visit the exercism.io Lua language page.


Conversation with James Edward Gray II https://twitter.com/jeg2

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local accumulate = require('accumulate')

describe('accumulate', function()
  local function square(x) return x * x end

  it('should accumulate over an empty array', function()
    assert.are.same({}, accumulate({}, square))

  it('should accumulate over an array with a single element', function()
    assert.are.same({ 4 }, accumulate({ 2 }, square))

  it('should accumulate over an array with several elements', function()
    assert.are.same({ 1, 4, 9 }, accumulate({ 1, 2, 3 }, square))

  it('should accumulate over an array with a different function', function()
    assert.are.same({ 'HELLO', 'WORLD' }, accumulate({ 'hello', 'world' }, string.upper))

  it('should not modify the input array', function()
    local input = { 1, 2, 3 }
    accumulate(input, square)
    assert.are.same({ 1, 2, 3 }, input)
local function accumulate(input, func)
  local output = {}
  for k, v in pairs(input) do
    output[k] = func(input[k])
  return output
return accumulate

Community comments

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Avatar of ryanplusplus

One more tip: you can return the function directly to make things a bit shorter: return function(input, func) local output = {} for k, v in pairs(input) do output[k] = func(input[k]) end return output end

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