Published at Aug 22 2019
·
0 comments

Instructions

Test suite

Solution

Given a number n, determine what the nth prime is.

By listing the first six prime numbers: 2, 3, 5, 7, 11, and 13, we can see that the 6th prime is 13.

If your language provides methods in the standard library to deal with prime numbers, pretend they don't exist and implement them yourself.

Execute the tests with:

```
$ mix test
```

In the test suites, all but the first test have been skipped.

Once you get a test passing, you can unskip the next one by
commenting out the relevant `@tag :pending`

with a `#`

symbol.

For example:

```
# @tag :pending
test "shouting" do
assert Bob.hey("WATCH OUT!") == "Whoa, chill out!"
end
```

Or, you can enable all the tests by commenting out the
`ExUnit.configure`

line in the test suite.

```
# ExUnit.configure exclude: :pending, trace: true
```

If you're stuck on something, it may help to look at some of the available resources out there where answers might be found.

A variation on Problem 7 at Project Euler http://projecteuler.net/problem=7

It's possible to submit an incomplete solution so you can see how others have completed the exercise.

```
defmodule NthPrimeTest do
use ExUnit.Case
# @tag :pending
test "first prime" do
assert Prime.nth(1) == 2
end
@tag :pending
test "second prime" do
assert Prime.nth(2) == 3
end
@tag :pending
test "sixth prime" do
assert Prime.nth(6) == 13
end
@tag :pending
test "100th prime" do
assert Prime.nth(100) == 541
end
@tag :pending
test "weird case" do
catch_error(Prime.nth(0))
end
end
```

```
ExUnit.start()
ExUnit.configure(exclude: :pending, trace: true)
```

```
defmodule Prime do
@doc """
Generates the nth prime.
"""
@spec nth(non_neg_integer) :: non_neg_integer
def nth(count) when count > 0 do
primes()
|> Enum.at(count - 1)
end
defp primes do
Stream.iterate(2, &(&1 + 1))
|> Stream.reject(&composite?/1)
end
defp composite?(2), do: false
defp composite?(number) do
2..(number - 1)
|> Enum.any?(&no_remainder?(number, &1))
end
defp no_remainder?(number1, number2), do: rem(number1, number2) == 0
end
```

A huge amount can be learned from reading other people’s code. This is why we wanted to give exercism users the option of making their solutions public.

Here are some questions to help you reflect on this solution and learn the most from it.

- What compromises have been made?
- Are there new concepts here that you could read more about to improve your understanding?

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