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to Gigasecond in the Crystal Track

Published at Jun 19 2019 · 0 comments
Instructions
Test suite
Solution

Calculate the moment when someone has lived for 10^9 seconds.

A gigasecond is 10^9 (1,000,000,000) seconds.

Setup

Follow the setup instructions for Crystal here:

http://exercism.io/languages/crystal

More help installing can be found here:

http://crystal-lang.org/docs/installation/index.html

Making the Test Suit Pass

Execute the tests with:

$ crystal spec

In each test suite all but the first test have been skipped.

Once you get a test passing, you can unskip the next one by changing pending to it.

Source

Chapter 9 in Chris Pine's online Learn to Program tutorial. http://pine.fm/LearnToProgram/?Chapter=09

Submitting Incomplete Solutions

It's possible to submit an incomplete solution so you can see how others have completed the exercise.

gigasecond_spec.cr

require "spec"
require "../src/*"

describe "Gigasecond" do
  describe "#from" do
    it "finds gigsecond from 2011_04_25" do
      result = Gigasecond.from(Time.utc(2011, 4, 25, 0, 0, 0))
      result.should eq Time.utc(2043, 1, 1, 1, 46, 40)
    end

    pending "finds gigsecond from 1977_06_13" do
      result = Gigasecond.from(Time.utc(1977, 6, 13, 0, 0, 0))
      result.should eq Time.utc(2009, 2, 19, 1, 46, 40)
    end

    pending "finds gigsecond from 1959_07_19" do
      result = Gigasecond.from(Time.utc(1959, 7, 19, 0, 0, 0))
      result.should eq Time.utc(1991, 3, 27, 1, 46, 40)
    end

    pending "finds gigsecond with full_time specified" do
      result = Gigasecond.from(Time.utc(2015, 1, 24, 22, 0, 0))
      result.should eq Time.utc(2046, 10, 2, 23, 46, 40)
    end

    pending "finds gigsecond with full_time with day rollover" do
      result = Gigasecond.from(Time.utc(2015, 1, 24, 23, 59, 59))
      result.should eq Time.utc(2046, 10, 3, 1, 46, 39)
    end

    pending "test_with_your_birthday" do
    end
  end
end
module Gigasecond
  def self.from(start_time)
    Time.epoch(start_time.epoch + 1_000_000_000)
  end
end

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