Published at Jan 30 2019
·
0 comments

Instructions

Test suite

Solution

Convert a number to a string, the contents of which depend on the number's factors.

- If the number has 3 as a factor, output 'Pling'.
- If the number has 5 as a factor, output 'Plang'.
- If the number has 7 as a factor, output 'Plong'.
- If the number does not have 3, 5, or 7 as a factor, just pass the number's digits straight through.

- 28's factors are 1, 2, 4,
**7**, 14, 28.- In raindrop-speak, this would be a simple "Plong".

- 30's factors are 1, 2,
**3**,**5**, 6, 10, 15, 30.- In raindrop-speak, this would be a "PlingPlang".

- 34 has four factors: 1, 2, 17, and 34.
- In raindrop-speak, this would be "34".

Run the tests with:

```
bats raindrops_test.sh
```

After the first test(s) pass, continue by commenting out or removing the `skip`

annotations prepending other tests.

A variation on a famous interview question intended to weed out potential candidates. http://jumpstartlab.com

`Bash`

is a language to write scripts that works closely with various system utilities,
like `sed`

, `awk`

, `date`

and even other programming languages, like `Python`

.
This track does not restrict the usage of these utilities, and as long as your solution is portable
between systems and does not require installing third party applications, feel free to use them to solve the exercise.

For an extra challenge, if you would like to have a better understanding of the language,
try to re-implement the solution in pure `Bash`

, without using any external tools.

It's possible to submit an incomplete solution so you can see how others have completed the exercise.

```
#!/usr/bin/env bash
@test "the sound for 1 is 1" {
#skip
run bash raindrops.sh 1
[ "$status" -eq 0 ]
[ "$output" == "1" ]
}
@test "the sound for 3 is Pling" {
skip
run bash raindrops.sh 3
[ "$status" -eq 0 ]
[ "$output" == "Pling" ]
}
@test "the sound for 5 is Plang" {
skip
run bash raindrops.sh 5
[ "$status" -eq 0 ]
[ "$output" == "Plang" ]
}
@test "the sound for 7 is Plong" {
skip
run bash raindrops.sh 7
[ "$status" -eq 0 ]
[ "$output" == "Plong" ]
}
@test "the sound for 6 is Pling as it has a factor 3" {
skip
run bash raindrops.sh 6
[ "$status" -eq 0 ]
[ "$output" == "Pling" ]
}
@test "2 to the power 3 does not make a raindrop sound as 3 is the exponent not the base" {
skip
run bash raindrops.sh 8
[ "$status" -eq 0 ]
[ "$output" == "8" ]
}
@test "the sound for 9 is Pling as it has a factor 3" {
skip
run bash raindrops.sh 9
[ "$status" -eq 0 ]
[ "$output" == "Pling" ]
}
@test "the sound for 10 is Plang as it has a factor 5" {
skip
run bash raindrops.sh 10
[ "$status" -eq 0 ]
[ "$output" == "Plang" ]
}
@test "the sound for 14 is Plong as it has a factor of 7" {
skip
run bash raindrops.sh 14
[ "$status" -eq 0 ]
[ "$output" == "Plong" ]
}
@test "the sound for 15 is PlingPlang as it has factors 3 and 5" {
skip
run bash raindrops.sh 15
[ "$status" -eq 0 ]
[ "$output" == "PlingPlang" ]
}
@test "the sound for 21 is PlingPlong as it has factors 3 and 7" {
skip
run bash raindrops.sh 21
[ "$status" -eq 0 ]
[ "$output" == "PlingPlong" ]
}
@test "the sound for 25 is Plang as it has a factor 5" {
skip
run bash raindrops.sh 25
[ "$status" -eq 0 ]
[ "$output" == "Plang" ]
}
@test "the sound for 27 is Pling as it has a factor 3" {
skip
run bash raindrops.sh 27
[ "$status" -eq 0 ]
[ "$output" == "Pling" ]
}
@test "the sound for 35 is PlangPlong as it has factors 5 and 7" {
skip
run bash raindrops.sh 35
[ "$status" -eq 0 ]
[ "$output" == "PlangPlong" ]
}
@test "the sound for 49 is Plong as it has a factor 7" {
skip
run bash raindrops.sh 49
[ "$status" -eq 0 ]
[ "$output" == "Plong" ]
}
@test "the sound for 52 is 52" {
skip
run bash raindrops.sh 52
[ "$status" -eq 0 ]
[ "$output" == "52" ]
}
@test "the sound for 105 is PlingPlangPlong as it has factors 3, 5 and 7" {
skip
run bash raindrops.sh 105
[ "$status" -eq 0 ]
[ "$output" == "PlingPlangPlong" ]
}
@test "the sound for 3125 is Plang as it has a factor 5" {
skip
run bash raindrops.sh 3125
[ "$status" -eq 0 ]
[ "$output" == "Plang" ]
}
```

```
#!/usr/bin/env bash
set -o errexit
USAGE="Usage: raindrops.sh <integer>"
validate_args(){
if [ "$#" -ne 1 ]
then
echo "$USAGE"
exit 1
elif ! [ "$1" -eq "$1" ] 2>/dev/null
then
echo "$USAGE"
exit 1
fi
}
run(){
num="$1"
factors=()
if [ "$num" -eq 1 ]
then
echo -n "1"
exit 0
else
# Calculate the factors
for (( i=2; i<="$1"; i++ ));do
while [ $((num%i)) == 0 ];do
# Store in an array each of the factors we want to work with
# Note the space after each of 'em.
case "$i" in
1) factors+=("1")
;;
3) factors+=("Pling")
;;
5) factors+=("Plang")
;;
7) factors+=("Plong")
;;
*) # do nothing
;;
esac
num=$((num/i))
done
done
fi
# Loops the factors obtained to form a string
# dropping all duplicates.
# This relies in the factors being factorised
# as they appear (in order). Valid assumption?
for i in "${factors[@]}";
do
if [[ "$drops" =~ $i ]]; then
continue
else
#Concat
drops="$drops$i"
fi
done
# If empty, default to the number pass (does not have factors -> return number)
echo "${drops-$1}"
}
main(){
validate_args "$@"
run "$@"
}
main "$@"
```

Handcrafted and not very elegant, but gets the job done.

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