Sublist in Python
Write a function to determine if a list is a sublist of another list.
exercism fetch python sublist
Given two lists determine if the first list is contained within the second list, if the second list is contained within the first list, if both lists are contained within each other or if none of these are true.
Specifically, a list A is a sublist of list B if by dropping 0 or more elements from the front of B and 0 or more elements from the back of B you get a list that's completely equal to A.
- A = [1, 2, 3], B = [1, 2, 3, 4, 5], A is a sublist of B
- A = [3, 4, 5], B = [1, 2, 3, 4, 5], A is a sublist of B
- A = [3, 4], B = [1, 2, 3, 4, 5], A is a sublist of B
- A = [1, 2, 3], B = [1, 2, 3], A is equal to B
- A = [1, 2, 3, 4, 5], B = [2, 3, 4], A is a superlist of B
- A = [1, 2, 4], B = [1, 2, 3, 4, 5], A is not a superlist of, sublist of or equal to B
Sometimes it is necessary to raise an exception. When you do this, you should include a meaningful error message to indicate what the source of the error is. This makes your code more readable and helps significantly with debugging. Not every exercise will require you to raise an exception, but for those that do, the tests will only pass if you include a message.
To raise a message with an exception, just write it as an argument to the exception type. For example, instead of
raise Exception, you shold write:
raise Exception("Meaningful message indicating the source of the error")
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